Find the Duplicate Number

Problem

Given an array of integers nums containing n + 1 integers where each integer is in the range [1, n] inclusive.

There is only one repeated number in nums, return this repeated number.

You must solve the problem without modifying the array nums and uses only constant extra space.

Example 1:

Input: nums = [1,3,4,2,2]
Output: 2

Example 2:

Input: nums = [3,1,3,4,2]
Output: 3

Example 3:

Input: nums = [3,3,3,3,3]
Output: 3

Constraints:

  • 1 <= n <= 105
  • nums.length == n + 1
  • 1 <= nums[i] <= n
  • All the integers in nums appear only once except for precisely one integer which appears two or more times.

Follow up:

  • How can we prove that at least one duplicate number must exist in nums?
  • Can you solve the problem in linear runtime complexity?

Solution

I thought this was a XOR question, but it turns out that I misunderstood the prompt.

This is similar to the linked list cycle question.

class Solution {
    public int findDuplicate(int[] nums) {
        var slow = 0;
        var fast = 0;

        do {
            slow = nums[slow];
            fast = nums[nums[fast]];
        } while (slow != fast);

        fast = 0;
        while (slow != fast) {
            slow = nums[slow];
            fast = nums[fast];
        }

        return slow;
    }
}

Recent posts from blogs that I like

Painting poetry: John Keats

Paintings based on Endymion, The Eve of St. Agnes, and La Belle Dame Sans Merci, mainly from the Pre-Raphaelites.

via The Eclectic Light Company

Live blog: the 12th day of OpenAI - "Early evals for OpenAI o3"

via Simon Willison

Turing Machines

body { text-wrap: pretty; } @media (prefers-reduced-motion: reduce) { * { transition: none; animation: none; } } turing-machine { width: 100%; display: block; position: relative; padding-bottom: 1em; } turing-machine .program-container { position: relative; display: flex; justify-content: center; } ...

via Sam Rose