Implement strStr()

Problem

Given two strings needle and haystack, return the index of the first occurrence of needle in haystack, or -1 if needle is not part of haystack.

Example 1:

Input: haystack = "sadbutsad", needle = "sad"
Output: 0
Explanation: "sad" occurs at index 0 and 6.
The first occurrence is at index 0, so we return 0.

Example 2:

Input: haystack = "leetcode", needle = "leeto"
Output: -1
Explanation: "leeto" did not occur in "leetcode", so we return -1.

Constraints:

  • 1 <= haystack.length, needle.length <= 10^4
  • haystack and needle consist of only lowercase English characters.

Solution

O(n * m) time complexity.

class Solution {
    public int strStr(String haystack, String needle) {
        for (var h = 0; h <= haystack.length() - needle.length(); h++) {
            var ok = true;
            for (var n = 0; n < needle.length(); n++) {
                var ch = haystack.charAt(h + n);
                var cn = needle.charAt(n);
                if (ch != cn) {
                    ok = false;
                    break;
                }
            }
            if (ok) {
                return h;
            }
        }
        return -1;
    }
}

Recent posts from blogs that I like

From the Commedia dell’Arte to Punch and Judy 1

Pierrot, Harlequin and other characters from the early professional theatre seen in paintings by Watteau, Goya and others.

via The Eclectic Light Company

Bloom filters

The original motivation for the creation of Bloom filters is efficient set membership, using a probabilistic approach to significantly reduce the time and space required to reject items that are not members in a certain set. The data structure was proposed by Burton Bloom in a 1970 paper titled "Spa...

via Eli Bendersky

Two publishers and three authors fail to understand what "vibe coding" means

via Simon Willison