Logger Rate Limiter

Problem

Design a logger system that receives a stream of messages along with their timestamps. Each unique message should only be printed at most every 10 seconds (i.e. a message printed at timestamp t will prevent other identical messages from being printed until timestamp t + 10).

All messages will come in chronological order. Several messages may arrive at the same timestamp.

Implement the Logger class:

  • Logger() Initializes the logger object.
  • bool shouldPrintMessage(int timestamp, string message) Returns true if the message should be printed in the given timestamp, otherwise returns false.

Example 1:

Input
["Logger", "shouldPrintMessage", "shouldPrintMessage", "shouldPrintMessage", "shouldPrintMessage", "shouldPrintMessage", "shouldPrintMessage"]
[[], [1, "foo"], [2, "bar"], [3, "foo"], [8, "bar"], [10, "foo"], [11, "foo"]]
Output
[null, true, true, false, false, false, true]

Explanation
Logger logger = new Logger();
logger.shouldPrintMessage(1, "foo");  // return true, next allowed timestamp for "foo" is 1 + 10 = 11
logger.shouldPrintMessage(2, "bar");  // return true, next allowed timestamp for "bar" is 2 + 10 = 12
logger.shouldPrintMessage(3, "foo");  // 3 < 11, return false
logger.shouldPrintMessage(8, "bar");  // 8 < 12, return false
logger.shouldPrintMessage(10, "foo"); // 10 < 11, return false
logger.shouldPrintMessage(11, "foo"); // 11 >= 11, return true, next allowed timestamp for "foo" is 11 + 10 = 21

Constraints:

  • 0 <= timestamp <= 109
  • Every timestamp will be passed in non-decreasing order (chronological order).
  • 1 <= message.length <= 30
  • At most 104 calls will be made to shouldPrintMessage.

Solution

Using a Map

class Logger {
    Map<String, Integer> m = new HashMap<>();

    public boolean shouldPrintMessage(int timestamp, String message) {
        var t = m.getOrDefault(message, 0);
        if (timestamp >= t) {
            m.put(message, timestamp + 10);
            return true;
        }
        return false;
    }
}

Using a Queue

More space efficient

class Logger {
    static class Pair<K, V> {
        K k;
        V v;
        Pair(K k, V v) {
            this.k = k;
            this.v = v;
        }
    }

    Set<String> s = new HashSet<>();
    Queue<Pair<Integer, String>> q = new LinkedList<>();

    public boolean shouldPrintMessage(int timestamp, String message) {
        // garbage collect
        while (!q.isEmpty() && q.peek().k <= timestamp - 10) {
            var v = q.poll();
            s.remove(v.v);
        }

        if (s.contains(message)) {
            return false;
        } else {
            q.add(new Pair<>(timestamp, message));
            s.add(message);
            return true;
        }
    }
}

Recent posts from blogs that I like

solving my problems

happy easter

via bookbear express

Paintings for Easter Sunday: Don’t touch me

Noli me tangere, Latin from the Vulgate for "don't touch me", are the opening words of Jesus when first seen by Mary Magdalene after his Resurrection. Here are the paintings.

via The Eclectic Light Company

The Axios supply chain attack used individually targeted social engineering

via Simon Willison