Best Time to Buy and Sell Stock II

Problem

You are given an integer array prices where prices[i] is the price of a given stock on the ith day.

On each day, you may decide to buy and/or sell the stock. You can only hold at most one share of the stock at any time. However, you can buy it then immediately sell it on the same day.

Find and return the maximum profit you can achieve.

Example 1:

Input: prices = [7,1,5,3,6,4]
Output: 7
Explanation: Buy on day 2 (price = 1) and sell on day 3 (price = 5), profit = 5-1 = 4.
Then buy on day 4 (price = 3) and sell on day 5 (price = 6), profit = 6-3 = 3.
Total profit is 4 + 3 = 7.

Example 2:

Input: prices = [1,2,3,4,5]
Output: 4
Explanation: Buy on day 1 (price = 1) and sell on day 5 (price = 5), profit = 5-1 = 4.
Total profit is 4.

Example 3:

Input: prices = [7,6,4,3,1]
Output: 0
Explanation: There is no way to make a positive profit, so we never buy the stock to achieve the maximum profit of 0.

Constraints:

  • 1 <= prices.length <= 3 * 10^4
  • 0 <= prices[i] <= 10^4

Solution

class Solution {
    public int maxProfit(int[] prices) {
        var profit = 0;

        for (int i = 0; i < prices.length - 1; i++) {
            var sellPrice = prices[i + 1];
            var buyPrice = prices[i];
            var diff = sellPrice - buyPrice;
            if (diff > 0) {
                profit += diff;
            }
        }

        return profit;
    }
}

Recent posts from blogs that I like

Rewriting pycparser with the help of an LLM

pycparser is my most widely used open source project (with ~20M daily downloads from PyPI [1]). It's a pure-Python parser for the C programming language, producing ASTs inspired by Python's own. Until very recently, it's been using PLY: Python Lex-Yacc for the core parsing. In this post, I'll descri...

via Eli Bendersky

the disorientation of freedom

beyond words

via bookbear express

Distributing Go binaries like sqlite-scanner through PyPI using go-to-wheel

via Simon Willison